Evaluating formulas
Heron's formula
Find the area, A units² of the given triangle using the following rule
\(A=\sqrt{\dfrac{(a+b+c)\times(-a+b+c)\times(a-b+c)\times(a+b-c)}{16}}\), where a, b and c are the side lengths of the triangle.
Give your answer correct to one decimal place.
Solution
Let a = 5, b = 7 and c = 8.
A | =\(\sqrt{\dfrac{(a+b+c)\times(-a+b+c)\times(a-b+c)\times(a+b-c)}{16}}\) |
=\(\sqrt{\dfrac{(5+7+8)\times(-5+7+8)\times(5-7+8)\times(5+7-8)}{16}}\) | |
=\(\sqrt{\dfrac{20\times10\times6\times4}{16}}\)(Use a calculator.) | |
= 17.320... | |
= 17.3 cm² correct to one decimal place. |
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