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NARRATOR: Exercise six.

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Solve the equation x cubed +
2x squared + 3x plus 6 equals 0.

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So we first need to factorise
the left-hand side

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in order to be able to use
the null factor law,

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and in factorising a cubic,
we need to first identify one factor.

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And we do that by looking for
one root of this equation -

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so we're looking for a number that
we can substitute into the polynomial

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in order to make it 0.

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So I'm going to start with
the value of the polynomial at 1.

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And that's gonna give me
1 + 2 + 3 + 6

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which is in fact 12, so not 0.

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So therefore this graph goes through
the point (1, 12).

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That point isn't an x-intercept

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and that's not useful to us
in the factorisation.

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I'm also noticing from this

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that all the terms
in my polynomial are positive,

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and so I'm gonna need to be
substituting in a negative number

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in order to get 0.

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I also know that
the numbers I substitute in

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are gonna all have to be ...

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... if they're going to give me 0,
are going to need to be factors of 6

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because the only way the brackets
can expand out

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to give a constant term of 6
at the end

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is using factors of 6
in those brackets.

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So let's first have
a look at P at –1.

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So that's gonna give me
-1 + 2 – 3 + 6,

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which gives me 4,
which, again, isn't 0.

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So we know we need to
stick with the negative,

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so we'll try –2.

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That gives me –8 + 8 – 6 and + 6

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which is indeed 0.

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So that tells me that
(x + 2) is a factor

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in order to give me one of
my x-intercepts at x = –2.

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So now that
I've identified one factor,

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I need to divide my cubic
by that factor

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to determine the other factors.

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So I use long division
for this process.

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There are different ways
to go about doing this.

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There's synthetic division.

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You can also do it in
a sort of more linear fashion

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without actually writing out
any kind of division.

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At the end of the day, you do
all the same mathematical steps

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to determine the factor.

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It's just about what
you choose to write down.

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So I'm dividing the cubic
by the linear factor,

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so what we're looking at here
is we've got our cubic equation

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x cubed + 2x squared + 3x + 6,

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and we know that
that's equal to (x + 2)

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multiplied by some other factor.

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And obviously we can see

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from this linear
right up here on the right

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that the first term
in that bracket there

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is going to have to be x squared.

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And what we're doing to get that
x squared is we're asking ourselves,

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"Well, what would I need to multiply 
x by in order to get x cubed?"

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And that's what we do
in the long division as well.

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"What would I need to multiply x by
to get x cubed?"

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Well, that's x squared.

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And then I'm gonna expand that out,

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just as we would when
we're expanding out the brackets -

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we would do x times x squared
and also 2 times x squared.

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So we're gonna do
x squared times (x + 2)

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which is gonna give me
x cubed + 2x squared.

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And then we subtract this.

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And we've chosen x squared in order
that the x cubed will cancel out,

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and in fact we have
an interesting situation here

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where we've also got the 2x squareds
cancelling out.

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So 2x squared – 2x squared
gives me 0.

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And I'm gonna write "x squared" here

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just to maintain the sort of
place value of my columns.

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Then I bring down the next term,
+ 3x,

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and we repeat the process.

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So what would I need to multiply x by
to get 0x squared?

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Well, that would be 0x,

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so we're not going to have
an x term in our factor.

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And then we expand out.

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So 0x times 0x, that's 0x squared.

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0x times 2, 0x.

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Then we take away and we've got 3x.

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Bring down the next term,

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which is + 6.

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What will we need to

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multiply x by to get 3x?

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Well, that's 3.

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Expand out, so 3x + 6.

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Write that down here.

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And subtract, which leaves us with 0.

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And that's what we expect

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when we've divided by a factor,

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we know that we're going to get
no remainder.

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So what we've identified here is

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that x cubed + 2x squared + 3x + 6

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is equivalent to (x + 2)

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multiplied by (x squared + 3).

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So now we're looking to solve
this equation equal to 0.

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So we're looking to
solve that equal to 0.

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And we can now use
the null factor law.

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So we know that x + 2 might equal 0

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or x squared + 3 might equal 0.

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So we get x = –2,

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which is the solution that
we identified back at the beginning.

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And we also have x squared equals –3.

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So we'll be trying to square root
a negative number here,

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so we're going to get no solutions
from this factor.

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So in fact we have a cubic equation
with just one solution

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at x = –2.

