Solution of simple linear equations
We first look at the following question but simpler equations are on the next page.
Question 1
Look at this rule.
P = 4T + 2.
What is the value of T when P = 6?
Solution
| P | = 4T + 2 |
| When P | = 6 |
| 6 | = 4 × T + 2. |
We now solve the equation.
| 6 – 2 | = 4 × T + 2 − 2 | (Subtract 2 from both sides) | ||
| 4 | = 4 × T | |||
| \(\dfrac{4}{4}\) | = \(\dfrac{4\times T}{4}\) | (Divide both sides by 4) | ||
| 1 | = T. |
| Check: LHS | = 6 and RHS = 4 × 1 + 2 = 6. | |
| LHS | = RHS. |
When you are confident some of the steps can be left out.
| 4 × T + 2 | = 6 | |||
| 4 × T | = 4 | (Subtract 2 from both sides) | ||
| T | = 1. | (Divide both sides by 4) |
It is sometimes easy to solve a linear equation just by looking at it.
In fact, this equation can be solved in this manner. It can be seen that T = 1 by inspection.
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