Solution of simple linear equations

We first look at the following question but simpler equations are on the next page.

Question 1

Look at this rule.
P = 4T + 2.
What is the value of T when P = 6?

Solution

P = 4T + 2
When P = 6
6 = 4 × T + 2.

We now solve the equation.

6 – 2   = 4 × T + 2 − 2 (Subtract 2 from both sides)
4   = 4 × T    
\(\dfrac{4}{4}\)   = \(\dfrac{4\times T}{4}\)   (Divide both sides by 4)
1   = T.    

Check: LHS   = 6 and RHS = 4 × 1 + 2 = 6.
LHS   = RHS.

When you are confident some of the steps can be left out.

4 × T + 2   = 6  
4 × T   = 4   (Subtract 2 from both sides)
T   = 1.   (Divide both sides by 4)

It is sometimes easy to solve a linear equation just by looking at it.
In fact, this equation can be solved in this manner. It can be seen that T = 1 by inspection.